Suppose $C(x)=x^{2}-6 x+16$ represents the costs, in hundreds, to produce $x$ thousand pens. How many pens should be produced to minimize the cost? What is the minimum cost?
Number of pens to minimize cost: pens
Minimum cost: dollars
You have 1 attempt(s) remaining before you will receive a new version of this problem.
Note: You can earn partial credit on this problem.
Final Answer: The number of pens to minimize cost is \(\boxed{3000}\) and the minimum cost is \(\boxed{700}\).
Step 1 :The cost function is a quadratic function. The minimum point of a quadratic function \(f(x) = ax^2 + bx + c\) is given by \(-\frac{b}{2a}\). In this case, \(a=1\) and \(b=-6\).
Step 2 :So, the number of pens to minimize cost can be found by calculating \(-\frac{b}{2a}\).
Step 3 :The minimum cost can be found by substituting the number of pens that minimize cost into the cost function.
Step 4 :By substituting the values, we get the number of pens as \(3000\) and the minimum cost as \(700\).
Step 5 :Final Answer: The number of pens to minimize cost is \(\boxed{3000}\) and the minimum cost is \(\boxed{700}\).