Put the following equation in slope-intercept form: $y-2=-\frac{2}{3}(x-1)$
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y=
\]

Answer

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Answer

$\boxed{y=-\frac{2}{3}x+\frac{8}{3}}$ is the equation in slope-intercept form.

Steps

Step 1 ：Given the equation: $y-2=-\frac{2}{3}(x-1)$

Step 2 ：Distribute the $-\frac{2}{3}$ to both terms inside the parentheses: $y-2=-\frac{2}{3}x+\frac{2}{3}$

Step 3 ：Isolate y on one side of the equation: $y=-\frac{2}{3}x+\frac{8}{3}$

Step 4 ：$\boxed{y=-\frac{2}{3}x+\frac{8}{3}}$ is the equation in slope-intercept form.