\[
E=\left[\begin{array}{lll}
0 & 3 & 5 \\
5 & 5 & 2
\end{array}\right] \text { e } D=\left[\begin{array}{rr}
3 & 4 \\
3 & -2 \\
4 & -2
\end{array}\right]
\]

Seja $\mathrm{H}=\mathrm{ED}$. Calcule $\mathrm{H}$.

Step 1 ：Given two matrices E and D as follows: \[E=\left[\begin{array}{lll} 0 & 3 & 5 \\ 5 & 5 & 2 \end{array}\right]\] and \[D=\left[\begin{array}{rr} 3 & 4 \\ 3 & -2 \\ 4 & -2 \end{array}\right]\]

Step 2 ：We are asked to calculate the product of these two matrices, denoted as H. The product of two matrices is calculated by taking the dot product of the rows of the first matrix with the columns of the second matrix.

Step 3 ：The resulting matrix will have as many rows as the first matrix and as many columns as the second matrix. In this case, the resulting matrix H will have 2 rows and 2 columns.

Step 4 ：By performing the matrix multiplication, we get \[H=\left[\begin{array}{ll} 29 & -16 \\ 38 & 6 \end{array}\right]\]

Step 5 ：\(\boxed{H=\left[\begin{array}{ll} 29 & -16 \\ 38 & 6 \end{array}\right]}\)