Problem

Find $\frac{d y}{d x}$ using implicit differentiation.
\[
5 x^{3}=7 y^{2}-5 y
\]
\[
\frac{d y}{d x}=\square
\]

Answer

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Answer

Final Answer: The derivative of \(y\) with respect to \(x\) is \(\boxed{\frac{15x^2}{14y - 5}}\).

Steps

Step 1 :Given the equation \(5 x^{3}=7 y^{2}-5 y\), we are asked to find \(\frac{d y}{d x}\) using implicit differentiation.

Step 2 :Differentiate both sides of the equation with respect to \(x\). This gives us the equation \(15x^2 = (14y - 5) \cdot \frac{dy}{dx}\).

Step 3 :Solve the equation for \(\frac{dy}{dx}\). This gives us \(\frac{dy}{dx} = \frac{15x^2}{14y - 5}\).

Step 4 :Final Answer: The derivative of \(y\) with respect to \(x\) is \(\boxed{\frac{15x^2}{14y - 5}}\).

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