Question 21

We made a pot of tea and are waiting for it to cool. The temperature of the tea after $t$ minutes is given by $y (t) = 142 e^{- .04 t} + 70$ . How hot was the tea at time $t = 0$ ?
$100^{\circ} F$
$212^{\circ} F$
$142^{\circ} F$
$70^{\circ} F$
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Final Answer: $212^{\circ} F$

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Step 1 ：To find the temperature of the tea at time $t = 0$ , we need to substitute $t = 0$ into the given function $y (t) = 142 e^{- 0.04 t} + 70$ and calculate the value.

Step 2 ：Substituting $t = 0$ into the function, we get $y (0) = 142 e^{- 0.04 \cdot 0} + 70$ .

Step 3 ：Simplifying the expression, we have $y (0) = 142 e^{0} + 70$ .

Step 4 ：Since $e^{0}$ is equal to 1, the expression becomes $y (0) = 142 \cdot 1 + 70$ .

Step 5 ：Adding the values, we get $y (0) = 142 + 70$ .

Step 6 ：Calculating the sum, we find that $y (0) = 212$ .

Step 7 ：Final Answer: $212^{\circ} F$

Question 21 We made a pot of tea and are waiting for it to cool. The temperature of the tea after t minutes is given by y(t)=142e−.04t+70. How hot was the tea at time t=0 ?100∘F212∘F142∘F70∘FSubmit Question

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Question 21

We made a pot of tea and are waiting for it to cool. The temperature of the tea after $t$ minutes is given by $y (t) = 142 e^{- .04 t} + 70$ . How hot was the tea at time $t = 0$ ?
$100^{\circ} F$
$212^{\circ} F$
$142^{\circ} F$
$70^{\circ} F$
Submit Question