Differentiate the function.
\[
\begin{array}{l}
h(x)=e^{x^{6}+\ln (x)} \\
h^{\prime}(x)=\square
\end{array}
\]

Answer

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Answer

\(\boxed{h^{\prime}(x)=6x^{5}e^{x^{6}+\ln (x)} + \frac{e^{x^{6}+\ln (x)}}{x}}\) is the final answer

Steps

Step 1 ：Given the function \(h(x)=e^{x^{6}+\ln (x)}\)

Step 2 ：Differentiate the function to find \(h'(x)\)

Step 3 ：By applying the chain rule, the derivative of the function is \(h'(x) = 6x^{5}e^{x^{6}+\ln (x)} + \frac{e^{x^{6}+\ln (x)}}{x}\)

Step 4 ：\(\boxed{h^{\prime}(x)=6x^{5}e^{x^{6}+\ln (x)} + \frac{e^{x^{6}+\ln (x)}}{x}}\) is the final answer