Use a limit of Riemann sums to evaluate the definite integral.
\[
\begin{aligned}
\int_{3}^{5}(4 x-1) d x & =\lim _{n \rightarrow \infty} \sum_{i=1}^{n} \\
& =\lim _{n \rightarrow \infty} \\
& =
\end{aligned}
\]
Hint: This list of summation rules may be helpful.
The final answer is \(\boxed{30}\)
Step 1 :Set up the Riemann sum for the function \( f(x) = 4x - 1 \) over the interval \([3, 5]\)
Step 2 :Use the limit definition of the definite integral, taking the limit as \( n \) approaches infinity of the sum of \( f(x_i) \times \Delta x \)
Step 3 :Use the right endpoint of each subinterval as the sample point
Step 4 :Calculate the definite integral using the limit of Riemann sums
Step 5 :The final answer is \(\boxed{30}\)