S varies inversely as $G$. If $S$ is 7 when $G$ is 4.9 , find $S$ when $G$ is 7 .
a) Write the variation.
b) Find $S$ when $G$ is 7 .
a) How are these two variables related?
A.
\[
S=\frac{k}{G^{2}}
\]
B. $S=k G^{2}$
C. $S=k G$
D.
\[
S=\frac{k}{G}
\]
b) The quantity indicated is $\square$. (Type an integer or a decimal.)

Step 1 ：The problem states that S varies inversely as G. This means that as G increases, S decreases and vice versa. The relationship between S and G can be represented by the equation \(S = \frac{k}{G}\), where k is the constant of variation.

Step 2 ：We can find the value of k by substituting the given values of S and G into the equation. Given that S is 7 when G is 4.9, we substitute these values into the equation to get \(7 = \frac{k}{4.9}\). Solving for k, we get \(k = 7 \times 4.9 = 34.3\).

Step 3 ：Now that we have the value of k, we can find the value of S when G is 7 by substituting G = 7 into the equation. This gives us \(S = \frac{34.3}{7} = 4.9\).

Step 4 ：Final Answer: The quantity indicated is \(\boxed{4.9}\).