Problem

Arrange the following rational numbers in ascending order: \(-\frac{3}{4}\), \(\frac{5}{6}\), \(-\frac{2}{3}\), \(\frac{1}{2}\)

Answer

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Answer

Finally, since all negative numbers are less than positive numbers, put the negative numbers first. So the final order is \(-\frac{3}{4}\), \(-\frac{2}{3}\), \(\frac{1}{2}\), \(\frac{5}{6}\)

Steps

Step 1 :First, compare the two positive rational numbers \(\frac{5}{6}\) and \(\frac{1}{2}\). Since \(\frac{5}{6} > \frac{1}{2}\), arrange them as \(\frac{1}{2}\), \(\frac{5}{6}\)

Step 2 :Next, compare the two negative rational numbers \(-\frac{3}{4}\) and \(-\frac{2}{3}\). Since \(-\frac{3}{4} < -\frac{2}{3}\), arrange them as \(-\frac{3}{4}\), \(-\frac{2}{3}\)

Step 3 :Finally, since all negative numbers are less than positive numbers, put the negative numbers first. So the final order is \(-\frac{3}{4}\), \(-\frac{2}{3}\), \(\frac{1}{2}\), \(\frac{5}{6}\)

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