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1.) Solve by graphing. Write your answer as an ordered pair.
$$\begin{array}{l}y=-x-1\\ 4x-3y=24\end{array}$$

Step 1 ：Understand the problem: We are given two equations and we are asked to solve them by graphing. The solution will be the point where the two lines intersect on the graph.

Step 2 ：Rearrange the equations in slope-intercept form $y=mx+b$. The first equation is already in this form: $y=-x-1$. The second equation can be rearranged as follows: $4x-3y=24$ to $y=\frac{4}{3}x-8$.

Step 3 ：Graph the equations. For $y=-x-1$, the y-intercept is -1 and the slope is -1. So you would start at point (0, -1) and then go down 1 and over 1 to the right to find another point, (1, -2). For $y=\frac{4}{3}x-8$, the y-intercept is -8 and the slope is $\frac{4}{3}$. So you would start at point (0, -8) and then go up 4 and over 3 to the right to find another point, (3, -4).

Step 4 ：Find the intersection point. The intersection point of the two lines is the solution to the system of equations. By graphing, you would find that the two lines intersect at point (6, -7).

Step 5 ：Check the solution. Substitute x = 6 and y = -7 into both original equations to check if they are true. For $y=-x-1$: $-7=-6-1$, which is true. For $4x-3y=24$: $24=24-21$, which is also true. So, the solution to the system of equations is the ordered pair (6, -7).

Step 6 ：$\boxed{{\displaystyle (6,-7)}}$ is the solution to the system of equations.