Problem

Compute 0ln(2)/4e4x(e4x+4)7dx

Answer

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Answer

54(e4x+4)6+21/4+44(e4x+4)6

Steps

Step 1 :Let u=e4x+4, then du=4e4xdx

Step 2 :Change the limits of integration to match the substitution: lower limit u(0)=5, upper limit u(ln(2)/4)=21/4+4

Step 3 :Rewrite the integral in terms of u and du: 14u7du

Step 4 :Integrate to find 54u6 evaluated from 5 to 21/4+4

Step 5 :Plug in the limits of integration: 54(21/4+4)6+54(5)6

Step 6 :Simplify the expression

Step 7 :54(e4x+4)6+21/4+44(e4x+4)6

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