Problem

In a school, 60% of the students play basketball, 45% of the students play baseball, and 30% of the students play both sports. If a student is selected at random, what is the probability that the student plays basketball or baseball?

Answer

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Answer

Step 2: Substitute the given values into the formula: \(P(A \cup B) = 0.60 + 0.45 - 0.30\).

Steps

Step 1 ：Step 1: We need to find the probability of the student playing basketball or baseball. As these events are not mutually exclusive, we use the formula for the probability of either of two events occurring, which is: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).

Step 2 ：Step 2: Substitute the given values into the formula: \(P(A \cup B) = 0.60 + 0.45 - 0.30\).

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