How many lines are determined by 16 points, no 3 of which are collinear?
This que
The number of lines is $\square$.

Step 1 ：We are given 16 points, no 3 of which are collinear. We need to find out how many lines are determined by these points.

Step 2 ：A line is determined by any two points. Since no three points are collinear, any two points will determine a unique line.

Step 3 ：Therefore, the problem is equivalent to finding the number of combinations of 16 points taken 2 at a time.

Step 4 ：This can be calculated using the combination formula: \(C(n, k) = \frac{n!}{(n-k)!k!}\), where n is the total number of items, k is the number of items to choose, and '!' denotes factorial.

Step 5 ：Substituting the given values into the formula, we get \(C(16, 2) = \frac{16!}{(16-2)!2!}\).

Step 6 ：Solving this, we find that the number of lines is 120.

Step 7 ：Final Answer: The number of lines is \(\boxed{120}\).