3) $\begin{array}{l}x-y=11 \\ 2 x+y=19\end{array}$
Final Answer: The solution to the system of equations is \(\boxed{x = 10}\) and \(\boxed{y = -1}\).
Step 1 :Given the system of linear equations: \(x - y = 11\) and \(2x + y = 19\)
Step 2 :We can solve this system by using the elimination method. By adding the two equations, we can eliminate y.
Step 3 :Adding the two equations gives us \(3x = 30\).
Step 4 :Solving for x, we get \(x = 10\).
Step 5 :Substituting \(x = 10\) into the first equation \(x - y = 11\), we can solve for y.
Step 6 :Solving for y, we get \(y = -1\).
Step 7 :Final Answer: The solution to the system of equations is \(\boxed{x = 10}\) and \(\boxed{y = -1}\).