Use the formula for the probability of the complement of an event.
Two dice are tossed. Let $E$ be the event of getting a sum of at least 4 .
Which of the following describes the event $E^{C}$ ?
getting a sum less than 4
getting a sum less than 3
getting a sum not equal to 4
getting a sum greater than 4

How many elements are in the event $E^{C}$ ?

What is the probability of the following? (Enter your probabilities as fractions.)
\[
\begin{array}{l}
P\left(E^{C}\right)= \\
P(E)=
\end{array}
\]

Step 1 ：Define the event $E$ as getting a sum of at least 4 when two dice are tossed.

Step 2 ：The complement of this event, $E^{C}$, is getting a sum less than 4.

Step 3 ：Consider all the possible outcomes when two dice are tossed that result in a sum less than 4. The possible outcomes are (1,1), (1,2), (2,1).

Step 4 ：Therefore, there are 3 elements in the event $E^{C}$.

Step 5 ：The total number of outcomes when two dice are tossed is 36 (6 outcomes for the first die and 6 for the second).

Step 6 ：The probability of an event is calculated as the number of favorable outcomes divided by the total number of outcomes.

Step 7 ：So, the probability of $E^{C}$ is \(\frac{3}{36} = \frac{1}{12}\).

Step 8 ：The probability of $E$ is 1 - the probability of $E^{C}$, so $P(E) = 1 - \frac{1}{12} = \frac{11}{12}$.

Step 9 ：\(\boxed{\text{The event } E^{C} \text{ is getting a sum less than 4. There are 3 elements in the event } E^{C}. \text{ The probability of } E^{C} \text{ is } \frac{1}{12} \text{ and the probability of } E \text{ is } \frac{11}{12}.}\)