Find an equation for the line that passes through the points $(-1,-1)$ and $(5,1)$
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Step 1 ：Find the slope using the formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Step 2 ：Substitute the coordinates of the given points: \((-1,-1)\) and \((5,1)\)

Step 3 ：Calculate the slope: \(m = \frac{1 - (-1)}{5 - (-1)} = \frac{2}{6} = \frac{1}{3}\)

Step 4 ：Choose one of the given points, let's use \((-1,-1)\)

Step 5 ：Substitute the values into the point-slope form: \(y - (-1) = \frac{1}{3}(x - (-1))\)

Step 6 ：Simplify the equation: \(y + 1 = \frac{1}{3}(x + 1)\)

Step 7 ：Multiply both sides by 3 to eliminate the fraction: \(3y + 3 = x + 1\)

Step 8 ：Rearrange the equation: \(x - 3y = -2\)

Step 9 ：The equation for the line that passes through the points \((-1,-1)\) and \((5,1)\) is \(x - 3y = -2\)