Find the equation of the line parallel to the line $4x-2y=6$ and passing through the point $(1,2)$

Step 1 ：Step1: Convert the equation of the line into slope-intercept form ($y=mx+b$), where $m$ is the slope. The slope of a parallel line would be the same. So, rearrange $4x-2y=6$ to slope-intercept form to find the slope.

Step 2 ：Step2: $4x-2y=6$ can be written as $2y=4x-6$, and then $y=2x-3$. So, the slope $m$ of the line is 2.

Step 3 ：Step3: Use the point-slope form of a line, which is $y-y1=m(x-x1)$, where $(x1,y1)$ is a given point on the line (in this case, $(1,2)$) and $m$ is the slope of the line. Substituting the given point and the slope into the equation gives us the equation of the line.

Step 4 ：Step4: Substituting $m=2$, $x1=1$, and $y1=2$ into $y-y1=m(x-x1)$ gives $y-2=2(x-1)$.

Step 5 ：Step5: Simplify the equation to slope-intercept form to get the equation of the line.