Given the equation of a hyperbola as (4x^2 - 9y^2 = 36), find the vertex form of this hyperbola.

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Accepted Answer

Step:1 ：Step 1: Rearrange the equation so that it equals 1: (frac{x^2}{9} - frac{y^2}{4} = 1)Step:2 ：Step 2: Recognize the standard form of the equation of a hyperbola: (frac{(x-h)^2}{a^2} - frac{(y-k)^2}{b^2}=1).Step:3 ：Step 3: By comparison, we can see that h=0, k=0, a=3, and b=2.Step:4 ：Step 4: Substitute these values into the standard form equation.

Answer

Step: 1 ：Step 1: Rearrange the equation so that it equals 1: (frac{x^2}{9} - frac{y^2}{4} = 1)Step: 2 ：Step 2: Recognize the standard form of the equation of a hyperbola: (frac{(x-h)^2}{a^2} - frac{(y-k)^2}{b^2}=1).Step: 3 ：Step 3: By comparison, we can see that h=0, k=0, a=3, and b=2.Step: 4 ：Step 4: Substitute these values into the standard form equation.

Given the equation of a hyperbola as \(4x^2 - 9y^2 = 36\), find the vertex form of this hyperbola.

Answer

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