Is $(1,2)$ a solution to this system of inequalities?
\[
\begin{array}{l}
2 x+8 y \leq 20 \\
x+3 y< 17
\end{array}
\]
yes
no

Step 1 ：Substitute x=1 and y=2 into the first inequality: 2x + 8y ≤ 20, we get \(2*1 + 8*2 ≤ 20\).

Step 2 ：Substitute x=1 and y=2 into the second inequality: x + 3y < 17, we get \(1 + 3*2 < 17\).

Step 3 ：Calculate these expressions to see if they hold true.

Step 4 ：For the first inequality, \(2*1 + 8*2 = 18\) which is less than or equal to 20, so the first inequality holds true.

Step 5 ：For the second inequality, \(1 + 3*2 = 7\) which is less than 17, so the second inequality holds true.

Step 6 ：Since both inequalities hold true when x=1 and y=2, the point (1,2) is a solution to the system of inequalities.

Step 7 ：Final Answer: \(\boxed{\text{yes}}\)