Divide the expression (frac{6x^2 - 5x - 1}{3x + 2}) by (2x - 1).

Question

Accepted Answer

Step:1 ：First, we divide the numerator and denominator of the first fraction by (2x - 1): (frac{6x^2 - 5x - 1}{2x - 1}) divided by (frac{3x + 2}{2x - 1}).Step:2 ：In order to divide by a fraction, we multiply by its reciprocal. Thus, we get (frac{6x^2 - 5x - 1}{2x - 1} times frac{2x - 1}{3x + 2}).Step:3 ：This simplifies to (frac{6x^2 - 5x - 1}{3x + 2}).

Answer

Step: 1 ：First, we divide the numerator and denominator of the first fraction by (2x - 1): (frac{6x^2 - 5x - 1}{2x - 1}) divided by (frac{3x + 2}{2x - 1}).Step: 2 ：In order to divide by a fraction, we multiply by its reciprocal. Thus, we get (frac{6x^2 - 5x - 1}{2x - 1} times frac{2x - 1}{3x + 2}).Step: 3 ：This simplifies to (frac{6x^2 - 5x - 1}{3x + 2}).

Divide the expression $\frac{6 x^{2} - 5 x - 1}{3 x + 2}$ by $2 x - 1$ .

Answer

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Divide the expression 6x2−5x−13x+2 by 2x−1.

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Popular Problems

Divide the expression $\frac{6 x^{2} - 5 x - 1}{3 x + 2}$ by $2 x - 1$ .