Factorize the sum of cubes (x^3 + 8)

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Accepted Answer

Step:1 ：The sum of cubes can be factorized using the formula (a^3 + b^3 = (a + b)(a^2 - ab + b^2)). Thus, for (x^3 + 8), (a) corresponds to (x), and (b) corresponds to (2), as (2^3 = 8)Step:2 ：By substituting (a) and (b) into the formula, we get (x^3 + 2^3 = (x + 2)(x^2 - 2x + 2^2))Step:3 ：Simplifying the above expression gives us (x^3 + 8 = (x + 2)(x^2 - 2x + 4))

Answer

Step: 1 ：The sum of cubes can be factorized using the formula (a^3 + b^3 = (a + b)(a^2 - ab + b^2)). Thus, for (x^3 + 8), (a) corresponds to (x), and (b) corresponds to (2), as (2^3 = 8)Step: 2 ：By substituting (a) and (b) into the formula, we get (x^3 + 2^3 = (x + 2)(x^2 - 2x + 2^2))Step: 3 ：Simplifying the above expression gives us (x^3 + 8 = (x + 2)(x^2 - 2x + 4))

Factorize the sum of cubes \(x^3 + 8\)

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