Problem

The following table shows the distribution of murders by type of Weapon weapon for murder cases in a particular country over the past 12 years. Complete parts (a) through (e).
\begin{tabular}{ll}
Handgun & 0.473 \\
\hline Rifle & 0.022 \\
\hline Shotgun & 0.035 \\
\hline Unknown firearm & 0.147 \\
\hline Knives & 0.131 \\
\hline Hands, fists, etc. & 0.058 \\
\hline Other & 0.134
\end{tabular}
A. If 1000 murders were randomly selected, exactly of them would have resulted from a rifle or shotgun.
B. If 1000 murders were randomly selected, we would expect about 57 of them to have resulted from a rifle or shotgun.
(c) What is the probability that a randomly selected murder resulted from a handgun, rifle, or shotgun?
$\mathrm{P}($ handgun, rifle, or shotgun $)=0.53$
(Type a decimal rounded to three decimal places as needed.)

Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice.
A. If 1000 murders were randomly selected, we would expect about $\square$ of them to have resulted from a handgun, rifle, or shotgun.
B. If 1000 murders were randomly selected, exactly $\square$ of them would have resulted from a handgun, rifle, or shotgun.

Answer

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Answer

Final Answer: The probability that a randomly selected murder resulted from a handgun, rifle, or shotgun is \(\boxed{0.53}\)

Steps

Step 1 :The question is asking for the probability that a randomly selected murder resulted from a handgun, rifle, or shotgun. This can be calculated by adding the probabilities of each of these events.

Step 2 :Given probabilities are: handgun = 0.473, rifle = 0.022, shotgun = 0.035

Step 3 :Add these probabilities: 0.473 + 0.022 + 0.035 = 0.53

Step 4 :Final Answer: The probability that a randomly selected murder resulted from a handgun, rifle, or shotgun is \(\boxed{0.53}\)

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