Problem

Find the quadratic equation whose solutions are \(2\) and \(-3\).

Answer

Expert–verified
Hide Steps
Answer

Expand the equation to get the quadratic equation: \(x^2 + x - 6 = 0\)

Steps

Step 1 ：If the solutions of a quadratic equation are \(x_1\) and \(x_2\), then the quadratic equation can be expressed as \( (x - x_1)(x - x_2) = 0 \)

Step 2 ：Substitute \(x_1 = 2\) and \(x_2 = -3\) into the equation, we get: \( (x - 2)(x - (-3)) = 0 \)

Step 3 ：Expand the equation to get the quadratic equation: \(x^2 + x - 6 = 0\)

link_gpt

Popular Problems

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find $y^{\prime}$ if $y=\ln \… 3. (3pts) Cherry trees in a c… More