Find the center-radius form of the equation of the circle described and graph it.
center $(0,-2)$, radius 6

Type the center-radius form of the equation of the circle.

Answer

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Answer

The center-radius form of the equation of the circle is $\boxed{(x - 0)^2 + (y + 2)^2 = 36}$.

Steps

Step 1 ：The general form of the equation of a circle with center at $(h, k)$ and radius $r$ is $(x - h)^2 + (y - k)^2 = r^2$.

Step 2 ：In this case, the center of the circle is at $(0, -2)$ and the radius is $6$.

Step 3 ：We can substitute these values into the general form to get the equation of the circle.

Step 4 ：The center-radius form of the equation of the circle is $\boxed{(x - 0)^2 + (y + 2)^2 = 36}$.