A neighborhood group goes to the movies every Saturday night. Last week, they purchased 29 adult tickets and 17 youth tickets for $\$ 254$. This week they purchased 21 adult tickets and 22 youth tickets for $\$ 213$. Find the cost of one adult ticket.
$\$ 7$
$\$ 3$
$\$ 9$
$\$ 6$
Thus, the cost of one adult ticket is \(\boxed{7}\) dollars.
Step 1 :Let's denote the cost of one adult ticket as 'a' and the cost of one youth ticket as 'y'.
Step 2 :From the first week's purchase, we can form the equation \(29a + 17y = 254\).
Step 3 :From the second week's purchase, we can form the equation \(21a + 22y = 213\).
Step 4 :These form a system of linear equations that we can solve to find the values of 'a' and 'y'.
Step 5 :Solving this system, we find that 'a' equals 7 and 'y' equals 3.
Step 6 :Thus, the cost of one adult ticket is \(\boxed{7}\) dollars.