Question 9, 8.3.5-T
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Use technology to find the P-value for the hypothesis test described below.
The claim is that for a smartphone carrier's data speeds at airports, the mean is $\mu=11.00 \mathrm{Mbps}$. The sample size is $n=28$ and the test statistic is $t=-2.485$.

P-value $=\square$ (Round to three decimal places as needed.)

Step 1 ：The question is asking for the P-value of a hypothesis test. The test statistic is given as \(t=-2.485\) and the sample size is \(n=28\). This is a t-test, and the P-value can be found using the cumulative distribution function (CDF) of the t-distribution. The CDF gives the probability that a random variable is less than or equal to a certain value. Since the test statistic is negative, we are looking for the probability that a random variable from the t-distribution is less than or equal to \(-2.485\). This is a one-tailed test.

Step 2 ：Given that the sample size \(n = 28\) and the test statistic \(t = -2.485\), the degrees of freedom is calculated as \(df = n - 1 = 27\).

Step 3 ：The p-value is calculated to be approximately 0.009723603372797669. This is the probability of observing a test statistic as extreme as \(t=-2.485\) under the null hypothesis.

Step 4 ：Final Answer: The P-value is \(\boxed{0.010}\) (rounded to three decimal places).