Let
\[
\begin{array}{l}
U=\{1,2,3,4,5,6,7\} \\
A=\{4,5,6,7\}
\end{array}
\]
List the members of each set, using set braces.
\[
A^{\prime}=\{\}
\]
(Use a comma to separate answers as needed.)
Therefore, the members of the set \(A'\) are \(\boxed{1, 2, 3}\).
Step 1 :Let the universal set U be \(U=\{1,2,3,4,5,6,7\}\) and the set A be \(A=\{4,5,6,7\}\).
Step 2 :The complement of set A in the universal set U, denoted as \(A'\), is the set of all elements in U that are not in A.
Step 3 :So, we need to find all the elements in U that are not in A.
Step 4 :The elements in U that are not in A are \(1, 2, 3\).
Step 5 :Therefore, the members of the set \(A'\) are \(\boxed{1, 2, 3}\).