Problem

In a random sample of 892 college students in the United States, 620 say they skip at least one class per week.

Find the point estimate for the proportion parameter for this population. Write your answer as a decimal rounded to three decimal places.
0.695
0.50
0.305
0.272

Answer

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Answer

Final Answer: \(\boxed{0.695}\)

Steps

Step 1 :In a random sample of 892 college students in the United States, 620 say they skip at least one class per week.

Step 2 :We need to find the point estimate for the proportion parameter for this population. The point estimate is calculated by dividing the number of students who skip class by the total number of students.

Step 3 :Let's denote the total number of students as \(N\) and the number of students who skip class as \(n\). In this case, \(N = 892\) and \(n = 620\).

Step 4 :The point estimate is calculated as follows: \(\frac{n}{N}\).

Step 5 :Substituting the given values into the formula, we get: \(\frac{620}{892}\).

Step 6 :The point estimate for the proportion parameter for this population is approximately 0.695 when rounded to three decimal places.

Step 7 :Final Answer: \(\boxed{0.695}\)

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