If g(x)=left(frac{1}{3}right)^{x}, find g(-3)

Question

Accepted Answer

Step:1 ：(g(-3) = left(frac{1}{3}right)^{-3})Step:2 ：Rewrite the expression using the property (a^{-n} = frac{1}{a^n}): (g(-3) = frac{1}{left(frac{1}{3}right)^3})Step:3 ：Calculate (left(frac{1}{3}right)^3 = frac{1}{3} * frac{1}{3} * frac{1}{3} = frac{1}{27})Step:4 ：Substitute (frac{1}{27}) into the expression: (g(-3) = frac{1}{frac{1}{27}})Step:5 ：Dividing by a fraction is the same as multiplying by its reciprocal: (g(-3) = 1 * frac{27}{1} = 27)Step:6 ：(boxed{g(-3) = 27})

Answer

Step: 1 ：(g(-3) = left(frac{1}{3}right)^{-3})Step: 2 ：Rewrite the expression using the property (a^{-n} = frac{1}{a^n}): (g(-3) = frac{1}{left(frac{1}{3}right)^3})Step: 3 ：Calculate (left(frac{1}{3}right)^3 = frac{1}{3} * frac{1}{3} * frac{1}{3} = frac{1}{27})Step: 4 ：Substitute (frac{1}{27}) into the expression: (g(-3) = frac{1}{frac{1}{27}})Step: 5 ：Dividing by a fraction is the same as multiplying by its reciprocal: (g(-3) = 1 * frac{27}{1} = 27)Step: 6 ：(boxed{g(-3) = 27})

If $g(x)=\left(\frac{1}{3}\right)^{x}$, find $g(-3)$

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