2. Solve the system by Elimination.
\[
\begin{array}{l}
8 x+6 y=2 \\
6 x+4 y=4
\end{array}
\]

Step 1 ：The system of equations is: \(8x + 6y = 2\) and \(6x + 4y = 4\)

Step 2 ：Subtract the second equation from the first to eliminate y: \((8x + 6y) - (6x + 4y) = 2 - 4\)

Step 3 ：This simplifies to: \(2x + 2y = -2\)

Step 4 ：Simplify this equation by dividing every term by 2: \(x + y = -1\)

Step 5 ：Substitute \(x = -1 - y\) into the second equation of the original system: \(6(-1 - y) + 4y = 4\)

Step 6 ：This simplifies to: \(-6 - 6y + 4y = 4\)

Step 7 ：Simplifying further gives: \(-2y = 10\)

Step 8 ：Dividing by -2 gives: \(y = -5\)

Step 9 ：Substitute \(y = -5\) into \(x + y = -1\) gives: \(x = -1 - (-5) = 4\)

Step 10 ：So the solution to the system of equations is \(\boxed{x = 4}\), \(\boxed{y = -5}\)