Simplify the expression ( frac{4x^3y^2z^4}{2x^2y^2z^2} )

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Accepted Answer

Step:1 ：First, divide each of the coefficients: ( frac{4}{2} = 2 )Step:2 ：Next, subtract the exponents of the variables: ( x^{3-2} = x^1, y^{2-2} = y^0, z^{4-2} = z^2 )Step:3 ：Remember that any number or variable to the power of 0 equals 1, so ( y^0 = 1 )Step:4 ：Finally, multiply the results together: ( 2 cdot x cdot 1 cdot z^2 = 2xz^2 )

Answer

Step: 1 ：First, divide each of the coefficients: ( frac{4}{2} = 2 )Step: 2 ：Next, subtract the exponents of the variables: ( x^{3-2} = x^1, y^{2-2} = y^0, z^{4-2} = z^2 )Step: 3 ：Remember that any number or variable to the power of 0 equals 1, so ( y^0 = 1 )Step: 4 ：Finally, multiply the results together: ( 2 cdot x cdot 1 cdot z^2 = 2xz^2 )

Simplify the expression \( \frac{4x^3y^2z^4}{2x^2y^2z^2} \)

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