If A=(35−12) and B=(2−134), find the matrix C such that C=2A−3B.
C=(6−610+3−2−94−12)
Step 1 :C=2A−3B→C=2(35−12)−3(2−134)
Step 2 :C=(610−24)−(6−3912)
Step 3 :C=(6−610+3−2−94−12)