Complete the table of ordered pairs for the linear equation.
\[
7 x+9 y=2
\]
Answer
Therefore, the completed table of ordered pairs for the linear equation \(7x + 9y = 2\) is: \[\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \frac{2}{9} \\ \hline 1 & \frac{-5}{9} \\ \hline -1 & 1 \\ \hline \end{array}\]
Step 1 ：Let x = 0. Substitute x = 0 into the equation, we get: \(7*0 + 9y = 2\), which simplifies to \(9y = 2\), so \(y = \frac{2}{9}\). The ordered pair is (0, \(\frac{2}{9}\)).
Step 2 ：Let x = 1. Substitute x = 1 into the equation, we get: \(7*1 + 9y = 2\), which simplifies to \(9y = -5\), so \(y = \frac{-5}{9}\). The ordered pair is (1, \(\frac{-5}{9}\)).
Step 3 ：Let x = -1. Substitute x = -1 into the equation, we get: \(7*(-1) + 9y = 2\), which simplifies to \(9y = 9\), so \(y = 1\). The ordered pair is (-1, 1).
Step 4 ：Therefore, the completed table of ordered pairs for the linear equation \(7x + 9y = 2\) is: \[\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \frac{2}{9} \\ \hline 1 & \frac{-5}{9} \\ \hline -1 & 1 \\ \hline \end{array}\]
