Problem

Expand \(\cos^2x\) using double-angle formulas.

Answer

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Answer

We need to express \(\cos^2x\) in terms of \(\cos 2x\), so we rearrange the second double-angle formula to solve for \(\cos^2x\): \(\cos^2x = \frac{\cos2x + 1}{2}\)

Steps

Step 1 :First, recall the double-angle formula for cosine: \(\cos2x = 1 - 2\sin^2x\) or \(\cos2x = 2\cos^2x - 1\).

Step 2 :We need to express \(\cos^2x\) in terms of \(\cos 2x\), so we rearrange the second double-angle formula to solve for \(\cos^2x\): \(\cos^2x = \frac{\cos2x + 1}{2}\)

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