Find the ordered pair solution for the following linear equation: 2x+3y=6
Step 2: Now we set x=0 and solve for y: 2∗0+3y=6→3y=6→y=2, so the second ordered pair is (0,2).
Step 1 :Step 1: We start by setting y=0 and solve for x: 2x+3∗0=6→2x=6→x=3, so the first ordered pair is (3,0).
Step 2 :Step 2: Now we set x=0 and solve for y: 2∗0+3y=6→3y=6→y=2, so the second ordered pair is (0,2).