Problem

In $2000,37 \%$ of registered births in the United States were to teenage mothers. A sociologist thinks it is lower in her town. She samples 96 births and finds 38 are to teenage mothers.
(a) Write the sample proportion as a fraction. You do not need to reduce this fraction.
\[
\hat{p}=
\]
(b) Convert the sample proportion to a decimal. Round your answer to 2 decimal places.
\[
\hat{p}=
\]
(c) Convert the sample proportion to a percentage. Round your answer to the nearest whole percentage.
\[
\hat{p}=
\]
\[
\%
\]

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Answer

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Answer

So, the sample proportion as a percentage is approximately \(\boxed{40\%}\).

Steps

Step 1 :Calculate the sample proportion as a fraction by dividing the number of successes (teenage mothers) by the total number of trials (total births). In this case, the number of successes is 38 and the total number of trials is 96. So, the sample proportion as a fraction is \(\hat{p}=\frac{38}{96}\).

Step 2 :Convert the sample proportion to a decimal by dividing the numerator by the denominator. So, \(\hat{p}=\frac{38}{96} \approx 0.40\).

Step 3 :Convert the sample proportion to a percentage by multiplying the decimal by 100. So, \(\hat{p}=0.40 \times 100 = 40\%\).

Step 4 :So, the sample proportion as a percentage is approximately \(\boxed{40\%}\).

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