\begin{tabular}{|c|c|}
\cline { 2 - 2 } \multicolumn{1}{c|}{} & Glycerol \\
\hline $\mathrm{m}(\mathrm{g})$ & 105 \\
\hline $\mathrm{T}_{\mathrm{i}}\left({ }^{\circ} \mathrm{C}\right)$ & 24 \\
\hline $\mathrm{T}_{\mathrm{f}}\left({ }^{\circ} \mathrm{C}\right)$ & 42 \\
\hline $\mathrm{C}\left(\mathrm{J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)$ & 2.43 \\
\hline
\end{tabular}
The chart on the left shows the data for a sample of glycerol being mixed with another liquid.
What is the change in temperature of the glycerol?
Remember: $\Delta T=T_{f}-T_{i}$
Answer
Final Answer: The change in temperature of the glycerol is \(\boxed{18}\) degrees Celsius.
Step 1 ：Given the initial temperature (T_i) of the glycerol is 24 degrees Celsius and the final temperature (T_f) is 42 degrees Celsius.
Step 2 ：The change in temperature (delta_T) can be calculated by subtracting the initial temperature from the final temperature. This is represented by the formula \(\Delta T=T_{f}-T_{i}\).
Step 3 ：Substitute the given values into the formula: \(\Delta T=42-24\).
Step 4 ：Calculate the difference to find the change in temperature: \(\Delta T=18\).
Step 5 ：Final Answer: The change in temperature of the glycerol is \(\boxed{18}\) degrees Celsius.
