The function $f$ is defined as follows.
\[
f(x)=\left\{\begin{array}{ll}
3 x & \text { if } x \neq 0 \\
3 & \text { if } x=0
\end{array}\right.
\]
(a) Find the domain of the function.
(b) Locate any intercepts.
(c) Graph the function.
(d) Based on the graph, find the range.
(e) Is $f$ continuous on its domain?
The function \(f\) is continuous on its domain because the function is defined for all real numbers and there are no breaks or jumps in the graph of the function.
Step 1 :The domain of the function is all real numbers because there are no restrictions on the values that x can take in the function \(f(x)\).
Step 2 :The y-intercept is at \((0,3)\) because when \(x=0\), \(f(x)=3\). The x-intercept is at \((1,3)\) because when \(f(x)=0\), \(x=1\).
Step 3 :To graph the function, we plot the points \((0,3)\) and \((1,3)\) and draw a line through them. The line will be a straight line with a slope of 3, passing through the y-axis at \((0,3)\).
Step 4 :Based on the graph, the range of the function is all real numbers because the line extends infinitely in both the positive and negative y-directions.
Step 5 :The function \(f\) is continuous on its domain because the function is defined for all real numbers and there are no breaks or jumps in the graph of the function.