If (x = frac{pi}{6}), find the value of (frac{2cosx + sinx}{sinx})

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Accepted Answer

Step:1 ：Substitute (x = frac{pi}{6}) into the given equation, we get: (frac{2cosfrac{pi}{6} + sinfrac{pi}{6}}{sinfrac{pi}{6}})Step:2 ：Using the trigonometric values for (frac{pi}{6}), we substitute (cosfrac{pi}{6} = frac{sqrt{3}}{2}) and (sinfrac{pi}{6} = frac{1}{2}) into the equation, we get: (frac{2*frac{sqrt{3}}{2} + frac{1}{2}}{frac{1}{2}})Step:3 ：Simplify the equation to get: (frac{sqrt{3} + frac{1}{2}}{frac{1}{2}})Step:4 ：Divide each term in the numerator by (frac{1}{2}) to get: (2sqrt{3} + 1)

Answer

Step: 1 ：Substitute (x = frac{pi}{6}) into the given equation, we get: (frac{2cosfrac{pi}{6} + sinfrac{pi}{6}}{sinfrac{pi}{6}})Step: 2 ：Using the trigonometric values for (frac{pi}{6}), we substitute (cosfrac{pi}{6} = frac{sqrt{3}}{2}) and (sinfrac{pi}{6} = frac{1}{2}) into the equation, we get: (frac{2*frac{sqrt{3}}{2} + frac{1}{2}}{frac{1}{2}})Step: 3 ：Simplify the equation to get: (frac{sqrt{3} + frac{1}{2}}{frac{1}{2}})Step: 4 ：Divide each term in the numerator by (frac{1}{2}) to get: (2sqrt{3} + 1)

If $x = \frac{π}{6}$ , find the value of $\frac{2 c o s x + s i n x}{s i n x}$

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If x=π6, find the value of 2cosx+sinxsinx

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Popular Problems

If $x = \frac{π}{6}$ , find the value of $\frac{2 c o s x + s i n x}{s i n x}$