Find the real solutions of the following equation.
$$3x^3+4x^2-7x+2=0$$

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is (Simplify your answer. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers separate answers as needed. Type each answer only once.)
B. The solution set is $\varnothing$.

Step 1 ：Given the cubic equation $3x^3+4x^2-7x+2=0$.

Step 2 ：We need to find the real solutions of this equation.

Step 3 ：We can use the roots function to compute the roots of a polynomial with coefficients given in a list. The list represents the coefficients of a polynomial, from highest degree to the constant term. In this case, the coefficients are [3, 4, -7, 2].

Step 4 ：The roots of the equation are approximately -2.41421356, 0.66666667, and 0.41421356.

Step 5 ：Rounding to the nearest ten-thousandth, the roots are -2.4142, 0.6667, and 0.4142.

Step 6 ：Final Answer: The real solutions of the equation are $\boxed{{\displaystyle -2.4142,0.6667,0.4142}}$.