These data are the number of on-campus burglanes reported in a given year for nine western Pennsyivanla universities. $\begin{array}{llllllllll} is & 11 & 2 & 15 & 9 & 8 & 13 & 6 & 15 \end{array}$

For the above data set, find the mean, median, midrange, and mode, Round to one decimal place, if necessary.
Part: $0 / 4$
Part 1 of 4
(a) Find the mean.
The mean is $◻$ burglaries.
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Final Answer: The mean is $8.8$ burglaries.

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Step 1 ：Given data is the number of on-campus burglaries reported in a given year for nine western Pennsylvania universities: 11, 2, 15, 9, 8, 13, 6, 15.

Step 2 ：To find the mean, we sum up all the numbers and then divide by the count of numbers.

Step 3 ：Adding all the reported burglaries together gives us $11 + 2 + 15 + 9 + 8 + 13 + 6 + 15 = 79$ .

Step 4 ：We then divide this sum by the total number of universities, which is 9. So, the mean is $\frac{79}{9} = 8.777777777777779$ .

Step 5 ：Rounding to one decimal place, the mean is 8.8.

Step 6 ：Final Answer: The mean is $8.8$ burglaries.

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