Problem

(1 point)
Find the limit. Use I'Hospital's Rule where appropriate.
\[
\lim _{x \rightarrow \infty} \frac{4(\ln x)^{2}}{x}
\]

Limit:

Answer

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Answer

Final Answer: The limit is \(\boxed{0}\).

Steps

Step 1 :The given limit is of the form \(\frac{\infty}{\infty}\), which is an indeterminate form. Therefore, we can apply L'Hopital's Rule. L'Hopital's Rule states that the limit of a quotient of two functions as x approaches a certain value is equal to the limit of the quotients of their derivatives, provided the original limit is of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\).

Step 2 :We need to find the derivative of the numerator and the derivative of the denominator, and then find the limit of the quotient of these two derivatives as x approaches infinity.

Step 3 :The derivative of the numerator \(4\ln(x)^{2}\) is \(\frac{8\ln(x)}{x}\).

Step 4 :The derivative of the denominator x is 1.

Step 5 :The limit of the quotient of the derivatives as x approaches infinity is 0.

Step 6 :Therefore, by L'Hopital's Rule, the limit of the original function as x approaches infinity is also 0.

Step 7 :Final Answer: The limit is \(\boxed{0}\).

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