Problem

Points: 0 of 1
Establish the identity.
\[
1+\frac{\tan ^{2} \theta}{\sec \theta+1}=\sec \theta
\]

Simplify the numerator of the fraction from the left side by applying the appropriate Pythagorean Identity.
\[
1+\frac{\square}{\sec \theta+1} \text { (Do not factor.) }
\]

Answer

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Answer

Final Answer: The simplified numerator of the fraction from the left side of the equation is \(\boxed{\sec^2\theta - 1}\)

Steps

Step 1 :Establish the identity: \(1+\frac{\tan ^{2} \theta}{\sec \theta+1}=\sec \theta\)

Step 2 :Simplify the numerator of the fraction from the left side by applying the appropriate Pythagorean Identity: \(1+\frac{\square}{\sec \theta+1}\)

Step 3 :The Pythagorean Identity for trigonometric functions states that \(\tan^2\theta = \sec^2\theta - 1\). Substitute this into the equation to simplify the numerator of the fraction on the left side.

Step 4 :Final Answer: The simplified numerator of the fraction from the left side of the equation is \(\boxed{\sec^2\theta - 1}\)

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