Question 11, 7.2.17
HW Score: $71.11 \%, 10.67$ of 15 points
Points: 0 of 1
Find the Z-scores that separate the middle $60 \%$ of the distribution from the area in the tails of the standard normal distribution.
E Click the icon to view a table of areas under the normal curve.
The Z-scores are $\square$.
(Use a comma to separate answers as needed. Round to two decimal places as needed.)
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So, the final answer is \(\boxed{-0.84, 0.84}\).
Step 1 :The question is asking for the Z-scores that separate the middle 60% of the distribution from the area in the tails of the standard normal distribution. The standard normal distribution is symmetric around the mean, so the middle 60% of the distribution is equally divided on both sides of the mean. This means that 20% of the distribution is in each tail.
Step 2 :We can use the Z-table to find the Z-scores that correspond to the cumulative probabilities of 20% and 80%.
Step 3 :From the Z-table, we find that the lower Z-score is approximately -0.84 and the upper Z-score is approximately 0.84.
Step 4 :The Z-scores that separate the middle 60% of the distribution from the area in the tails of the standard normal distribution are approximately -0.84 and 0.84.
Step 5 :So, the final answer is \(\boxed{-0.84, 0.84}\).