The grades for 20 students on the most recent exam are given in the data table below. Round your answers to 2 decimal places as needed
$$\text{Unknown environment 'tabular'}$$

Mean $=$

Median $=$

Standard deviation $=$

Minimum score $=$

Highest score $=$

Step 1 ：First, list all the scores in ascending order: 41, 41, 42, 46, 49, 52, 54, 57, 58, 72, 73, 75, 76, 79, 82, 83, 85, 88, 92, 92

Step 2 ：Calculate the mean by summing all the scores and dividing by the number of scores: $\frac{41+41+42+46+49+52+54+57+58+72+73+75+76+79+82+83+85+88+92+92}{20}=68.35$

Step 3 ：Find the median by taking the average of the 10th and 11th scores: $\frac{58+72}{2}=65$

Step 4 ：Calculate the squared differences from the mean: $(41-68.35{)}^2,(41-68.35{)}^2,(42-68.35{)}^2,...,(92-68.35{)}^2$

Step 5 ：Calculate the average of these squared differences to get the variance: $\frac{(41-68.35{)}^2+(41-68.35{)}^2+(42-68.35{)}^2+...+(92-68.35{)}^2}{20}=291.1775$

Step 6 ：Take the square root of the variance to get the standard deviation: $\sqrt{291.1775}=17.06$

Step 7 ：The minimum score is the lowest score: $\boxed{{\displaystyle 41}}$

Step 8 ：The highest score is the highest score: $\boxed{{\displaystyle 92}}$

Step 9 ：So, the mean is $\boxed{{\displaystyle 68.35}}$, the median is $\boxed{{\displaystyle 65}}$, the standard deviation is $\boxed{{\displaystyle 17.06}}$, the minimum score is $\boxed{{\displaystyle 41}}$, and the highest score is $\boxed{{\displaystyle 92}}$