Find the maximum value of the quadratic function f(x)=−2x2+4x+3.
f(0.5)=−2(0.5)2+4∗0.5+3=3.5
Step 1 :The quadratic function f(x)=ax2+bx+c reaches its maximum or minimum value at x=−b2a. So, let's calculate x=−b2a for f(x)=−2x2+4x+3.
Step 2 :−b2a=−42∗(−2)=0.5
Step 3 :Substitute x=0.5 into the function f(x)=−2x2+4x+3 to find the maximum value.
Step 4 :f(0.5)=−2(0.5)2+4∗0.5+3=3.5