Find the maximum value of the quadratic function (f(x) = -2x^2 + 4x + 3).

Question

Accepted Answer

Step:1 ：The quadratic function (f(x) = ax^2 + bx + c) reaches its maximum or minimum value at (x = -frac{b}{2a}). So, let&#x27;s calculate (x = -frac{b}{2a}) for (f(x) = -2x^2 + 4x + 3).Step:2 ：(-frac{b}{2a} = -frac{4}{2*(-2)} = 0.5)Step:3 ：Substitute (x = 0.5) into the function (f(x) = -2x^2 + 4x + 3) to find the maximum value.Step:4 ：(f(0.5) = -2(0.5)^2 + 4*0.5 + 3 = 3.5)

Answer

Step: 1 ：The quadratic function (f(x) = ax^2 + bx + c) reaches its maximum or minimum value at (x = -frac{b}{2a}). So, let&#x27;s calculate (x = -frac{b}{2a}) for (f(x) = -2x^2 + 4x + 3).Step: 2 ：(-frac{b}{2a} = -frac{4}{2*(-2)} = 0.5)Step: 3 ：Substitute (x = 0.5) into the function (f(x) = -2x^2 + 4x + 3) to find the maximum value.Step: 4 ：(f(0.5) = -2(0.5)^2 + 4*0.5 + 3 = 3.5)

Find the maximum value of the quadratic function \(f(x) = -2x^2 + 4x + 3\).

Answer

Popular Problems