Problem

For the polynomial function f(x)=7(x9)(x+2)2 answer the following questions.
(a) List each real zero and its multiplicity.
(b) Determine whether the graph crosses or touches the x-axis at each x-intercept.
(c) Determine the maximum number of turning points on the graph.
(d) Determine the end behavior; that is, find the power function that the graph of f resembles for large values of |x|.
(a) Find any real zeros of f. Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.
A. The real zero of f is with multiplicity
(Type an exact answer, using radicals as needed. Type integers or fractions.)
B. The smallest zero of f is with multiplicity The largest zero of f is with multiplicity
(Type an exact answer, using radicals as needed. Type integers or fractions.)
C. The smallest zero of f is with multiplicity The middle zero of f is with multiplicity The largest zero of f is with multiplicity (Type an exact answer, using radicals as needed. Type integers or fractions.)
D. There are no real zeros.

Answer

Expert–verified
Hide Steps
Answer

Final Answer: The real zeros of the function f(x)=7(x9)(x+2)2 are x=2 with multiplicity 2 and x=9 with multiplicity 1. In Latex format, the answer is x=2 with multiplicity 2 and x=9 with multiplicity 1.

Steps

Step 1 :The real zeros of a polynomial function are the x-values for which the function equals zero. In this case, the function will be zero when either (x9) or (x+2)2 equals zero. So, we need to solve these two equations to find the real zeros.

Step 2 :The solutions to the equations are x = 9 and x = -2. However, since (x+2)2 is squared, the zero x = -2 has a multiplicity of 2, meaning it is a root of the polynomial twice. The zero x = 9 has a multiplicity of 1, as it is not raised to any power.

Step 3 :Final Answer: The real zeros of the function f(x)=7(x9)(x+2)2 are x=2 with multiplicity 2 and x=9 with multiplicity 1. In Latex format, the answer is x=2 with multiplicity 2 and x=9 with multiplicity 1.

link_gpt