A pyramid has a square base of side length 4 cm. Each of the triangular faces has a height of 6 cm. What is the surface area of the pyramid?

Step 1 ：The surface area of a pyramid is given by the formula \(A = B + \frac{1}{2}Psl\), where \(B\) is the area of the base, \(P\) is the perimeter of the base, and \(sl\) is the slant height. In this case, the base is a square, so \(B = s^2\) and \(P = 4s\), where \(s\) is the side length of the base. The slant height is the height of the triangular faces, which we'll call \(h_t\).

Step 2 ：First, we calculate the area of the base: \(B = s^2 = 4^2 = 16 \, cm^2\).

Step 3 ：Next, we calculate the perimeter of the base: \(P = 4s = 4 \times 4 = 16 \, cm\).

Step 4 ：Now we can find the surface area of the pyramid: \(A = B + \frac{1}{2}Psl = 16 + \frac{1}{2} \times 16 \times 6 = 16 + 48 = 64 \, cm^2\).