The Pyramid is an arena in Memphis, Tennessee. Its height is $321 \mathrm{ft}$, and its slant height is $436.5 \mathrm{ft}$. Find the length of the edge of the square base. Round the answer to the nearest tenth.
(1 point)
ft.

Step 1 ：The problem is asking for the length of the edge of the square base of the Pyramid. Given the height and the slant height, we can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In this case, the slant height is the hypotenuse, the height is one of the sides, and the half of the edge of the square base is the other side.

Step 2 ：We can set up the equation as follows: \((\text{half of the edge of the square base})^2 + \text{height}^2 = \text{slant height}^2\).

Step 3 ：Given that the height is 321 ft and the slant height is 436.5 ft, we can substitute these values into the equation.

Step 4 ：Solving this equation will give us the length of the edge of the square base. The half edge of the square base is approximately 295.7891985857496 ft.

Step 5 ：Since the edge of the square base is twice the half edge, we multiply the half edge by 2 to get the edge of the square base, which is approximately 591.6 ft.

Step 6 ：Final Answer: The length of the edge of the square base is \(\boxed{591.6}\) ft.