Use the properties of logarithms to write the logarithm in terms of $\log _{3}(5)$ and $\log _{3}(7)$.
\[
\log _{3}\left(\frac{7}{25}\right)
\]
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Final Answer: \(\boxed{\log _{3}(7) - 2\log _{3}(5)}\)
Step 1 :Given the expression \(\log _{3}\left(\frac{7}{25}\right)\)
Step 2 :Using the properties of logarithms, specifically the quotient rule, we can rewrite the expression as \(\log _{3}(7) - \log _{3}(25)\)
Step 3 :Next, we express 25 as \(5^2\) and apply the power rule of logarithms to rewrite \(\log _{3}(25)\) as \(2\log _{3}(5)\)
Step 4 :Substituting this back into our expression, we get \(\log _{3}(7) - 2\log _{3}(5)\)
Step 5 :Final Answer: \(\boxed{\log _{3}(7) - 2\log _{3}(5)}\)